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Explanation: because kclo3 get reduced to kcl.
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Sep 28, 2014 · 7. Decomposition of KClO3 is sometimes used to prepare small amounts of O2 in the laboratory: 2KClO3(s) 2 KCl(s) + 3 O2(g). How many grams of O2 can be prepared from 4.50 g of KClO3? Answer: NaH (g) = -55 kJ/mol BaCl 2(s) = -858 kJ/mol . Do any of the molecules in the reactants have any coefficients? Answer: Yes, NaH (g) 2 NaH (g) = 2 * (-55 kJ/mol) What is the general formula for Δ H? Answer: Energy of products – Energy of reactants = Δ H . Modify the Δ H equation for this chemical equation. (H 2 Ba (s) + 2 NaCl (s ...
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Mass-To-Mass Conversions. For the reaction shown, calculate how many grams of oxygen form when each of the following completely reacts: 2KClO3 (s)→2KCl (s)+3O2 (g) 1.) 2.76 grams of KClO3. 2.) 0.381 grams of KClO3. 3.) 85.3 kg of KClO3. From ΔG f ° values: [1ΔG f (K+1 (aq)) + 1ΔG f (Cl-1 (aq))] - [1ΔG f (KCl (s))] [1(-283.3) + 1(-131.25)] - [1(-408.32)] = -6.23000000000002 kJ-6.23 kJ ... 4HCl (aq) + 2S2O3-2(aq) →2S (s) + 2SO2(g) + 2H2O (l) + 4Cl-(aq) bilangan oksidasi S berubah dari …. a. +2 menjadi 0 dan +4 b. +5 menjadi +2 dan 0 c. +3 menjadi 0 dan +4 d. +6 menjadi -2 dan +4 e. +4 menjadi 0 dan +2. 12. Pada reaksi: Cr2O3(s) + KClO3(aq) + 4KOH(aq) → 2K2CrO4 + KCl(aq) + 2H2O(l) Pernyataan yang benar adalah… a.
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Miriel N. asked • 03/13/17 Consider the following reaction. 2KClO3(s) → 2KCl(s) + 3O2(g) How many grams of KCl are produced from the complete reaction of 14.7 mol of KClO3? If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 16.0 g of O2? 2 KClO3(s) 2 KCl(s) + 3 O2(g)
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helllppppppp meeeee! what is the coefficient of KClO3 when the equation KClO3(s) --> KCl(s) + O2(g) is balanced? a. 1 b. 4 c. 3 d. 2 Tags: Jan 22, 2020 · If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 42.0 g of O2? 2 KClO3(s) → 2 KCl(s) + 3 O2(g) Na (s) + Cl 2(g) ——-> NaCl (s) The skeleton equation thus provides us with a better means of expressing a chemical reaction, as compared to a word equation. However, if you carefully observe the above example equation, you will notice that, even though there are two chlorine atoms on the reaction side, there is but a single one on the ...